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A small test charge of 12 μC experiences a force of 6 mN. What is the electric field magnitude?

A) 250 N/C

B) 750 N/C

C) 1000 N/C

D) 500 N/C

Answer: D

Explanation: Use electric field = force ÷ charge with milli/micro conversion for the stated idealized conditions. Substitution gives 6 mN ÷ 12 μC = 500 N/C.

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