A 200 g gold sample has specific heat 0.13 J/(g·°C). How much heat raises it by 10 °C? Assume constant specific heat and no phase change.

A) 130 J

B) 26 J

C) 260 J

D) 520 J

Answer: C

Explanation: At approximately constant specific heat, q = mcΔT. Multiply 200 g by 0.13 J/(g·°C) and 10 °C to obtain 260 J.