Using rounded atomic masses, what percent by mass of C is in glucose (C6H12O6)?

A) 60.0%

B) 40.0%

C) 50.0%

D) 30.0%

Answer: B

Explanation: The formula mass is about 180 g/mol; C contributes 72 g per mole. Divide 72 by 180 and multiply by 100 to obtain about 40.0%.

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