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With Faraday constant 96,500 C/mol e⁻, how many moles of aluminium deposit from Al³⁺ using 38600 C?

By /

A) 0.4 mol

B) 0.266667 mol

C) 0.133333 mol

D) 0.0666667 mol

Answer: C

Explanation: First divide charge by Faraday constant to find moles of electrons. 38600/96,500 = 0.4 mol e⁻, then divide by 3 for 0.133333 mol metal.

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