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With Faraday constant 96,500 C/mol e⁻, how many moles of copper deposit from Cu²⁺ using 19300 C?

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A) 0.1 mol

B) 0.2 mol

C) 0.05 mol

D) 0.3 mol

Answer: A

Explanation: First divide charge by Faraday constant to find moles of electrons. 19300/96,500 = 0.2 mol e⁻, then divide by 2 for 0.1 mol metal.

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