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With Faraday constant 96,500 C/mol e⁻, how many moles of zinc deposit from Zn²⁺ using 28950 C?

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A) 0.3 mol

B) 0.075 mol

C) 0.45 mol

D) 0.15 mol

Answer: D

Explanation: First divide charge by Faraday constant to find moles of electrons. 28950/96,500 = 0.3 mol e⁻, then divide by 2 for 0.15 mol metal.

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