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95 mL of 0.8 M ZnSO₄ is diluted to 665 mL. What is the final molarity?

A) 5.6 M

B) 0.1 M

C) 0.8 M

D) 0.114286 M

Answer: D

Explanation: Dilution conserves solute amount, so C₁V₁ = C₂V₂. The final molarity is 0.8 × 95/665 = 0.114286 M.

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